How do you find the slope of the secant lines of #f(x) = -3x + 2 # through the points: (-4,(f(-4)) and (1,f(1))?
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To find the slope of the secant line between two points on the graph of a function ( f(x) ), you use the formula:
[ \text{Slope} = \frac{{f(x_2) - f(x_1)}}{{x_2 - x_1}} ]
Where ( (x_1, f(x_1)) ) and ( (x_2, f(x_2)) ) are the given points.
For the function ( f(x) = -3x + 2 ) and the given points ( (-4, f(-4)) ) and ( (1, f(1)) ), plug the x-values into the function to find the corresponding y-values, and then use the formula to calculate the slope.
[ f(-4) = -3(-4) + 2 = 14 ] [ f(1) = -3(1) + 2 = -1 ]
Now, plug these values into the formula:
[ \text{Slope} = \frac{{-1 - 14}}{{1 - (-4)}} = \frac{{-15}}{{5}} = -3 ]
So, the slope of the secant line through the points ( (-4, f(-4)) ) and ( (1, f(1)) ) is ( -3 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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