# How do you find the slope of the polar curve #r=3+8sin(theta)# at #theta=pi/6# ?

by converting into parametric equations,

By differentiating with respect to

by evaluating at

By differentiating with respect to

by evaluating at

So, the slope

The graph along with its tangent line at

I hope that this was helpful.

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To find the slope of the polar curve ( r = 3 + 8\sin(\theta) ) at ( \theta = \frac{\pi}{6} ), you need to differentiate the equation with respect to ( \theta ) and then evaluate it at ( \theta = \frac{\pi}{6} ).

- Differentiate ( r = 3 + 8\sin(\theta) ) with respect to ( \theta ) using the chain rule.
- Substitute ( \theta = \frac{\pi}{6} ) into the derivative obtained in step 1 to find the slope at that specific point.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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