How do you find the slope of the line with the given information A) #2x+y=7# B) the line is perpendicular to #y=10x + 7#?

Answer 1

We first rewrite the first equation in slope-intercept form.

(A) This is quite easy: subtract #2x# from both sides: #y=-2x+7# so the slope is #-2#
(B) If two lines are perpendicular, multiplying their slopes will allways give a result of #-1#. Let's call the slope we want to find #m# The equation is allready in slope-intercept form with a slope of #10#.
So: #m*10=-1->m=-1/10#
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Answer 2

To find the slope of a line given by the equation (2x + y = 7), first solve for (y) to put it in slope-intercept form, (y = mx + b), where (m) is the slope.

[2x + y = 7 \Rightarrow y = -2x + 7]

Thus, the slope of this line is (-2).

For part B, if the line is perpendicular to (y = 10x + 7), then its slope will be the negative reciprocal of the slope of (y = 10x + 7). The slope of (y = 10x + 7) is (10), so the slope of the line that is perpendicular to it will be (-\frac{1}{10}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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