How do you find the slope of the line whose equation is #2x – 4y = 10#?

Answer 1
Yo can rearrange your equation and "see" you slope as coeficient of #x#: isolating #y# you have: #y=1/2x-5/2#
So your slope is #1/2#
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Answer 2
The slope of the line is #1/2#.
The equation of a line in slope-intercept form is #y=mx + b#, where #m# is the slope, #b# is the y-intercept, and #x# and #y# are a point on the line.

In order to determine the slope from the given equation, do the following:

#2x - 4y = 10# (Subtract #2x# from both sides.)
#-4y = -2x + 10# (Divide both sides by -4.)
#y = (-2x)/(-4) + (10)/(-4)# (Simplify.)
#y = 1/2 x - (5)/(2)#
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Answer 3

Rearrange the equation into slope-intercept form: (y = \frac{1}{2}x - \frac{5}{2})
The coefficient of (x) is the slope.
So, the slope of the line is (\frac{1}{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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