How do you find the slope of the line passing through the points (0, 5) and (-2, -1)?

Answer 1

#y = 3x + 5#

The equation of line is: #y = mx + b# where: #m = (y_2-y_1)/(x_2-x_1) = (5 - (-1))/(0 - (-2)) = 6/2 = 3 # Note it is evident that b = 5; Why?

Now we know then: #y = 3x + b# Pick any point say (0,5); #y = 3(0) + 5; b = 5#

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Answer 2

Eva Adamson

To find the slope of the line passing through the points (0, 5) and (-2, -1), you use the formula:

[ \text{Slope} = \frac{{\text{change in } y}}{{\text{change in } x}} ]

Substitute the coordinates of the points into the formula:

[ \text{Slope} = \frac{{-1 - 5}}{{-2 - 0}} ]

[ \text{Slope} = \frac{{-6}}{{-2}} ]

[ \text{Slope} = \frac{3}{1} ]

[ \text{Slope} = 3 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.