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How do you find the slope of the line passing through (6,-3), (1, -13)?

Answer 1

Savannah Anderson

#"slope "=2#

#"calculate the slope m using the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(6,-3)" and "(x_2,y_2)=(1,-13)#

#rArrm=(-13-(-3))/(1-6)=(-10)/(-5)=2#

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Answer 2

Eva Adamson

To find the slope of a line passing through two points, you can use the formula:

[ \text{Slope} = \frac{{\text{change in } y}}{{\text{change in } x}} ]

Substitute the coordinates of the two points into the formula:

[ \text{Slope} = \frac{{-13 - (-3)}}{{1 - 6}} ]

[ \text{Slope} = \frac{{-13 + 3}}{{1 - 6}} ]

[ \text{Slope} = \frac{{-10}}{{-5}} ]

[ \text{Slope} = 2 ]

So, the slope of the line passing through (6,-3) and (1, -13) is ( 2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.