How do you find the slope of the line containing points with the coordinates (-4, -5) and (4, 4)?

Answer 1

#+9/8#

Slope (gradient) is all about rate of change.

You always read left to right on the x-axis (unless stated otherwise)

The left most #x# is the -4

Set point 1 as #P_1->(x_1,y_1)=(-4,-5)#

Set point 2 as #P_2->(x_2,y_2)=(4,4)#

Slope (gradient) is the change in up or down for a given amount of along.

If the change is down then the gradient is negative.
If the change is up then the gradient is positive.

Gradient is #P_2-P_1 ->("change in up or down")/("change in along") =(y_2-y_1)/(x_2-x_1)#

Set gradient as #m=(y_2-y_1)/(x_2-x_1)= (4-(-5))/(4-(-4)) =(4+5)/(4+4)=+9/8#

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Answer 2

To find the slope of the line containing the points (-4, -5) and (4, 4), you use the formula for slope: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ), where ( (x_1, y_1) ) and ( (x_2, y_2) ) are the coordinates of the two points. Substituting the given coordinates into the formula, you get ( m = \frac{{4 - (-5)}}{{4 - (-4)}} ). Simplify this expression to find the slope.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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