How do you find the slope of the graph #f(x)=3x^3-6# at (2,18)?
The value of the slope is
Here we have:
By signing up, you agree to our Terms of Service and Privacy Policy
To find the slope of the graph of ( f(x) = 3x^3 - 6 ) at the point ( (2,18) ), you need to find the derivative of the function and then evaluate it at ( x = 2 ). The derivative of ( f(x) ) is ( f'(x) = 9x^2 ). When ( x = 2 ), ( f'(2) = 9(2)^2 = 36 ). So, the slope of the graph at ( (2,18) ) is ( 36 ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the equation of the line normal to #f(x)=4/(2x-1) # at #x=0#?
- How do you use the limit definition of the derivative to find the derivative of #f(x)=-4x^3-3x^2+1#?
- What is the equation of the line tangent to # f(x)=x^2-(x-1)^3 # at # x=1 #?
- What is the equation of the tangent line of #f(x)=2x-3 # at any x?
- What is the equation of the normal line of #f(x)=sqrt(3x^2+2x)# at #x=2 #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7