# How do you find the slope of the graph #f(x)=(2x+1)^2# at (0,1)?

Using the chain rule of derivatives, and then plugging in a x value of 0 for the

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To find the slope of the graph of ( f(x) = (2x + 1)^2 ) at the point (0,1), you need to calculate the derivative of the function and then evaluate it at ( x = 0 ).

First, find the derivative of ( f(x) ): [ f'(x) = 2(2x + 1)(2) = 8x + 4 ]

Next, evaluate the derivative at ( x = 0 ): [ f'(0) = 8(0) + 4 = 4 ]

So, the slope of the graph of ( f(x) ) at the point (0,1) is ( 4 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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