# How do you find the slope of the curve #y^3-xy^2=4# at the point where y=2?

The slope of the curve is

We need to start by finding the x-coordinate.

Now we differentiate.

Hopefully this helps!

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ThenTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first,To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then,To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiateTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substituteTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate theTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute (To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equationTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y =To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitlyTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly withTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respectTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 \To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect toTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 )To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to (To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) intoTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( xTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into theTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x \To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resultingTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ).To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expressionTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). ThenTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression andTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then,To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solveTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substituteTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve forTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute (To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for (To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( yTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y =To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \fracTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dyTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 \To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 )To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dxTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) intoTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}}To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into theTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} \To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resultingTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ).To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expressionTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). ThisTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solveTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields theTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve forTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slopeTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for theTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope ofTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slopeTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of theTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope.To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curveTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiationTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve atTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation andTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the pointTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitutionTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point whereTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution,To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where (To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, theTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( yTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slopeTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y =To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope atTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at theTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the pointTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 \To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point whereTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ).To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( yTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiationTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y =To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation andTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitutionTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution,To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 \To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, theTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) isTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope isTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is (To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is foundTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found toTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \fracTo find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to beTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be (To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \fracTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{4To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \frac{{To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{4}To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \frac{{dyTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{4} \To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \frac{{dy}}{{To find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{4} ).To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \frac{{dy}}{{dxTo find the slope of the curve ( y^3 - xy^2 = 4 ) at the point where ( y = 2 ), first, differentiate the equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for the slope. After differentiation and substitution, the slope at the point where ( y = 2 ) is ( \frac{-3}{4} ).To find the slope of the curve at the point where ( y = 2 ), first differentiate the given equation implicitly with respect to ( x ). Then, substitute ( y = 2 ) into the resulting expression and solve for ( \frac{{dy}}{{dx}} ). This yields the slope of the curve at the point where ( y = 2 ). After differentiation and substitution, the slope is found to be ( \frac{{dy}}{{dx}} = \frac{{12x - 4}}{{3y^2 - 2xy}} ). Substituting ( y = 2 ), the slope at the point where ( y = 2 ) is ( \frac{{12x - 4}}{{12}} = x - \frac{1}{3} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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