How do you find the slope of a tangent line to the graph of the function #f(x)=3-5x# at (-1,8)?

Answer 1

slope #= -5#

Given: #f(x) = 3-5x# at #(-1, 8)#
Usually we find the slope by finding the first derivative and evaluating it at the #x# value of the point: #f'(-1)#
In the given case, we have a linear equation: #y = mx + b# The slope of the line is given as #m = -5#. This slope is the same everywhere along the line.
If you find #f'(x) = -5#.
#f'(-1) = -5# since it is a constant slope.
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Answer 2

To find the slope of a tangent line to the graph of a function at a specific point, you can use the derivative of the function. In this case, the function is f(x) = 3 - 5x. To find the derivative, you can apply the power rule, which states that the derivative of x^n is n*x^(n-1). Applying the power rule to the function f(x) = 3 - 5x, the derivative is f'(x) = -5.

To find the slope of the tangent line at a specific point, (-1,8) in this case, you substitute the x-coordinate of the point into the derivative. So, f'(-1) = -5. Therefore, the slope of the tangent line to the graph of f(x) = 3 - 5x at (-1,8) is -5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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