How do you find the slope of a line perpendicular to #y = 2 - 5x#?

Question

Eva Adamson · Accepted Answer

Slope of a line perpendicular to # y= -5 x +2 # is #1/5# Slope of the line, # y= -5 x +2 ; [y=m x+c]# is #m_1= -5# .The product of slopes of the perpendicular lines is #m_1*m_2=-1:.m_2=(-1)/m_1=(-1)/-5=1/5#. Therefore, slope of a line perpendicular to # y= -5 x +2 # is #1/5# [Ans]

Genesis Allen · Answer

To find perpendicular gradient, #m1 * m2 = -1#

Remember that the slope of the line is known as gradient, and is often represented as #m#

First rearrange the function into the gradient-intercept form #y = mx+c#:

#y = 5x - 2#

Here we can see that the gradient of the function is 5, because #m = 5#

Next use #m1 * m2 = -1# , to find the perpendicular gradient.

#5 * m2 = -1# #(5 * m2)/5 = -1/5# #m2 = -1/5#, or -0.2.

The perpendicular gradient is -0.2

Savannah Anderson · Answer

undefined To find the slope of a line perpendicular to y = 2 - 5x, you take the negative reciprocal of the coefficient of x in the given equation. So, the slope of the perpendicular line is 1/5.