How do you find the slope of a line perpendicular to #5x-2y=-1#?

Answer 1
Remember that given a slope, #m#, the slope perpendicular to it is #-1/m# (the negative of its inverse).
Re-write the given equation #5x-2y= -1# in slope-point form: #y=5/2x +1/2#
The slope of the given equation is #5/2# and the slope of a line perpendicular to it is #-2/5#
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Answer 2
The slope is: #(-2/5)#

Perpendicular lines' slopes are negative reciprocals.

#y = (5x+1)/2#
The slope of line #y# is: #5/2#
So #m * (5/2) = -1#
We need to find #m# to find the slope of the perpendicular line.
#m = (-2/5)#
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Answer 3

To find the slope of a line perpendicular to the given line 5x - 2y = -1, we first need to rewrite the equation in slope-intercept form (y = mx + b). Then, we identify the slope of the original line and use the fact that perpendicular lines have slopes that are negative reciprocals of each other. So, the slope of the perpendicular line would be the negative reciprocal of the slope of the original line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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