How do you find the slope of 7x+2y=6?

Answer 1

#"slope "=-7/2#

The equation of a line in #color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))# where m represents the slope and b, the y-intercept.
#"Rearrange "7x+2y=6" into this form"#

From both sides of the equation, subtract 7x.

#cancel(7x)cancel(-7x)+2y=6-7x=-7x+6#
#rArr2y=-7x+6#

divide every term by two on each side.

#(cancel(2) y)/cancel(2)=(-7)/2x+6/2#
#rArry=-7/2x+3larr" in form y =mx +b"#
#rArr"slope "=m=-7/2#
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Answer 2

To find the slope of the line represented by the equation (7x + 2y = 6), rearrange the equation into slope-intercept form (y = mx + b), where (m) represents the slope.

First, isolate (y) on one side: [ 2y = -7x + 6 ]

Then, divide both sides by (2): [ y = -\frac{7}{2}x + 3 ]

The coefficient of (x), which is (-\frac{7}{2}), represents the slope of the line. So, the slope of the line is (-\frac{7}{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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