How do you find the slope of #5x + 3y = -2#?

Answer 1

slope #=-5/3#

The equation of a line in #color(blue)"slope-intercept form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))# where m represents the slope and b, the y-intercept.

The advantage to having the equation in this form is that m and b can be extracted 'easily'.

Rearrange 5x + 3y = - 2 into this form.

leave 5y on the left and move 5x to the right.

subtract 5x from both sides

#cancel(5x)+3y-cancel(5x)=-2-5xrArr3y=-2-5x#

now divide both sides by 3

#(cancel(3) y)/cancel(3)=-2/3-(5)/3 x#

#rArr"slope" =-5/3#

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Answer 2

Ethan Adkins

To find the slope of the line represented by the equation 5x + 3y = -2, you first need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope.

Subtract 5x from both sides of the equation: 3y = -5x - 2
Divide both sides by 3 to isolate y: y = (-5/3)x - 2/3

Now, you can see that the coefficient of x, which is -5/3, represents the slope of the line. Therefore, the slope of the line represented by the equation 5x + 3y = -2 is -5/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.