How do you find the slope of #(-5, 6), (7, -8)#?

Answer 1

See a solution process below:

The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#
Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Changing the values from the problem's points yields:

#m = (color(red)(-8) - color(blue)(6))/(color(red)(7) - color(blue)(-5)) = (color(red)(-8) - color(blue)(6))/(color(red)(7) + color(blue)(5)) => -14/12 =>#
#(-(7 xx 2)/(6 xx 2)) => (-(7 xx color(red)(cancel(color(black)(2))))/(6 xx color(red)(cancel(color(black)(2))))) => -7/6#
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Answer 2

To find the slope of a line passing through two points ((x_1, y_1)) and ((x_2, y_2)), you can use the formula:

[ \text{Slope} = \frac{y_2 - y_1}{x_2 - x_1} ]

Using the given points (-5, 6) and (7, -8):

[ \text{Slope} = \frac{-8 - 6}{7 - (-5)} = \frac{-14}{12} = -\frac{7}{6} ]

So, the slope of the line passing through (-5, 6) and (7, -8) is (-\frac{7}{6}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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