How do you find the slope of #2x+3y-3=0#?

Answer 1

#-2/3#

Rearranging #2x+3y-3=0# we get #y=2/3[x]+1# and this is in slope intercept form , where the slope is #-2/3# [ie, the coefficient of# x#] and the [#1]# is the intercept value on the #y# axis

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Answer 2

Isaiah Anthony

To find the slope of the equation (2x + 3y - 3 = 0), rearrange it into slope-intercept form (y = mx + b), where (m) is the slope:

Subtract (2x) from both sides: (3y = -2x + 3)
Divide both sides by (3): (y = -\frac{2}{3}x + 1)

The slope (m) is (-\frac{2}{3}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.