How do you find the slope given P1(–1, 1) and P2(4, –4)?

Answer 1

#"slope "= -1#

The slope (gradient) is: #" "("change in y-axis")/("change in x-axis") = m#
Given: Point 1 #->P_1->(x_1,y_1)->(-1,1)# Point 2#->P_2->(x_2,y_2)->(4,-4)#
Gradient#=m-> (y_2-y_1)/(x_2-x_1)=((-4)-1)/(4-(-1))#
#m=(-5)/(5)= -1# '~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Note Two minus signs next to each other make a plus.

A minus is a minus and a plus next to each other.

When it comes to division, the result is plus if the signs are the same and minus if they are inconsistent.

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Answer 2

To find the slope given the points ( P_1(-1, 1) ) and ( P_2(4, -4) ), you use the formula ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Substituting the coordinates, you get ( m = \frac{{-4 - 1}}{{4 - (-1)}} ). Solving this yields ( m = -\frac{5}{5} ), which simplifies to ( m = -1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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