How do you find the slope given (c, d) and (c, 1/d)?
The slope is undefined and the line is a vertical line through
Whenever the
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To find the slope given the points ( (c, d) ) and ( (c, \frac{1}{d}) ), you use the formula:
[ \text{Slope} = \frac{\text{change in } y}{\text{change in } x} ]
Since both points have the same ( x )-coordinate (( c )), the change in ( x ) is 0. Therefore, the slope is undefined.
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To find the slope given points ((c, d)) and ((c, \frac{1}{d})), you can use the formula for slope, which is:
[ \text{Slope} = \frac{{\text{change in }} y}{{\text{change in }} x}} = \frac{{\text{difference in } y}}{{\text{difference in } x}} ]
Substituting the given points:
[ \text{Slope} = \frac{{\left(\frac{1}{d} - d\right)}}{{(c - c)}} ]
Simplifying further:
[ \text{Slope} = \frac{{\frac{1}{d} - d}}{{0}} ]
Since the denominator is zero, the slope is undefined. This means that the given points lie on a vertical line, and there is no slope associated with vertical lines.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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