How do you find the slope given (1, 5) and (1, -7)?

Answer 1

See a solution process below:

Because the #x# value for both points is the same, this means;
For each and every value of #y#; #x# will have the same value of #1#.

By definition this is a vertical line.

And, by definition, vertical lines have an undefined slope.

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Answer 2

To find the slope given the points (1, 5) and (1, -7), use the formula:

slope = (change in y) / (change in x)

First, subtract the y-coordinate of the first point from the y-coordinate of the second point: -7 - 5 = -12

Then, subtract the x-coordinate of the first point from the x-coordinate of the second point: 1 - 1 = 0

The slope is undefined because the change in x is 0, resulting in division by zero. This indicates that the line is vertical.

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Answer 3

To find the slope given two points (x1, y1) and (x2, y2), you can use the formula: [ \text{Slope} = \frac{y2 - y1}{x2 - x1} ] Plugging in the values: [ \text{Slope} = \frac{-7 - 5}{1 - 1} = \frac{-12}{0} ] Since the denominator is zero, the slope is undefined. This means that the line passing through the points (1, 5) and (1, -7) is a vertical line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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