How do you find the slope given (1/2, -1); (3, -3/4)?

Answer 1

The slope between #(1/2,-1)# and #(3,-3/4)# is #1/10#

#color(white)("XXXX")##m=(y_2-y_1)/(x_2-x_1)# gives the slope given two general points, #(x_1,y_1)# and #(x_2,y_2)#.
This becomes #color(white)("XXXX")##m = (-3/4 -(-1))/(3-1/2)# for the specific points #(1/2,-1)# and #(3,-3/4)#.
#1/4)/(5/2)# #color(white)("XXXXXXX")#
#1/10# #color(white)("XXXXXXX")
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Answer 2

To find the slope given the points (1/2, -1) and (3, -3/4), you can use the slope formula:

slope = (change in y) / (change in x)

Substitute the coordinates into the formula:

slope = (-3/4 - (-1)) / (3 - 1/2)

Then, simplify:

slope = (-3/4 + 1) / (3 - 1/2) slope = (-3/4 + 4/4) / (3 - 1/2) slope = (1/4) / (3 - 1/2)

Now, find a common denominator:

slope = (1/4) / (6/2 - 1/2) slope = (1/4) / (5/2)

Invert the denominator and multiply:

slope = (1/4) * (2/5) slope = 2/20 slope = 1/10

So, the slope of the line passing through the points (1/2, -1) and (3, -3/4) is 1/10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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