How do you find the slope for #x-5 = 0#?

Answer 1

The slope of #x-5=0# is "undefined".

#x-5 =0# or equivalently #x = 5# is a vertical line.
Slope for any two points #(x_1,y_1) and (x_2,y_2)# is defined as #(y_2-y_1)/(x_2-x_1)#
#x_2 and x_1# must both be #=5# based on the equation so any attempt to evaluate the slope results in an attempt to divide by zero.
#x-5=0# is a vertical line
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Answer 2

To find the slope for the equation ( x - 5 = 0 ), we first need to rewrite the equation in the slope-intercept form ( y = mx + b ), where ( m ) represents the slope. Since the equation ( x - 5 = 0 ) is already in a form where ( x ) is isolated, we can rewrite it as ( y = x - 5 ). In this equation, the coefficient of ( x ) is 1, which represents the slope. Therefore, the slope of the equation ( x - 5 = 0 ) is ( m = 1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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