How do you find the slope for 6x+4y=16?

Answer 1

The slope is #-3/2# or #-1.5#.

To find the slope, first make the equation in slope-intercept form (shown below) so that we can find the slope easlier:

To make #y# by itself, first subtract #color(blue)(6x)# from both sides of the equation:
#6x + 4y quadcolor(blue)(-quad6x) = 16 quadcolor(blue)(-quad6x)#

#4y = 16 - 6x#

Now divide both sides by #color(blue)4#:
#(4y)/color(blue)4 = (16-6x)/color(blue)4#

#y = 16/4 - 6/4x#

Simplify:
#y = 4 - 3/2x#

Therefore, the slope is #-3/2# or #-1.5#.

Hope this helps!

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Answer 2

To find the slope of the line given by the equation (6x + 4y = 16), rearrange the equation into slope-intercept form, (y = mx + b), where (m) is the slope. Then, isolate (y) to one side of the equation. After isolating (y), the coefficient of (x) will be the slope. So, in this case, the slope is (-\frac{3}{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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