How do you find the slope and y intercept of #4x-6y+3=0#?

Answer 1

slope # = 2/3 #
y-intercept #= 1/2#

We can "easily" extract the slope and y-intercept from the equation of a line in the form #color(red)(|bar(ul(color(white)(a/a)color(black)( y = mx + c )color(white)(a/a)|)))#, where m stands for the slope and c for the y-intercept.

We can achieve that by rearranging 4x - 6y + 3 = 0 into this form.

Remember to swap the signs as you move 4x and +3 to the right.

Consequently, dividing both sides by -6 yields: -6y = -4x-3.

# (y)/cancel(-6) # = (-4)/(-6) x + (-3)/(-6) #

2/3 x + 1/2 #rArr y

c = 1/2 # graph{2/3x+1/2 [-10, 10, -5, 5]} #rArr m = 2/3 " and "
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Answer 2

To find the slope and y-intercept of the equation 4x - 6y + 3 = 0, rearrange it into slope-intercept form (y = mx + b) by solving for y. Then identify the coefficient of x as the slope (m), and the constant term as the y-intercept (b).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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