How do you find the slope and y intercept of #2x+5=y#?

Answer 1

slope = 2
y-intercept = 5

the standard form of the equation is #y=mx + b#
#m=slope# b=y-intercept
#y=2x+5#
#2# is in the place of #m#, so it would be the slope #5# is in the place of #b#, so it would be the y-intercept
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Answer 2

#"slope "=2," y-intercept "=5#

#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#y=2x+5larrcolor(blue)"is in this form"#
#"with slope m "=2" and y-intercept, b "=5# graph{2x+5 [-10, 10, -5, 5]}
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Answer 3

To find the slope and y-intercept of the equation (2x + 5 = y), first rewrite it in slope-intercept form (y = mx + b). Then, identify the coefficient of (x) as the slope ((m)) and the constant term as the y-intercept ((b)). In this case, the slope ((m)) is (2) and the y-intercept ((b)) is (5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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