How do you find the slope and y intercept for #x + y = 1#?

Answer 1

I would write your equation in a way that allows me to "read" these information directly by isolating #y# on one side: #y=-x+1# ( I moved #x# to the right changing sign) so that you have the Slope-Intercept form: #y=#slope#*x+#(y-intercept) Now, the slope is the number in front of #x#, in this case #-1#. The y-intercept is the number alone, in this case #1#

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Answer 2

Jameson Allen

To find the slope and y-intercept for the equation (x + y = 1), we first rearrange the equation into slope-intercept form, (y = mx + b), where (m) is the slope and (b) is the y-intercept. So, let's solve for (y):

[y = -x + 1]

Comparing this with the slope-intercept form, we can see that the slope ((m)) is (-1) and the y-intercept ((b)) is (1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.