How do you find the slope and y-intercept for the line #x + y + 2 = 0#?

Answer 1

Slope: #-1#
#y#-intercept: #-2#.

To find the slope and the #y#-intercept of a line, you need to put it in the form
#y=mx+q#.
Then, #m# will be the slope and #q# the intercept.
In your case, it is very simple, because you only need to isolate the #y#, bringing the term #x+2# on the right hand, and thus changing its sign into #-x-2#. Once in the form #y=-x-2#, you'll have #m=-1# and #q=-2#.
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Answer 2

To find the slope and y-intercept for the line (x + y + 2 = 0), rearrange the equation to solve for (y):

[y = -x - 2]

The slope is -1 and the y-intercept is -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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