How do you find the slope and y intercept for #2x-y= 1#?

Answer 1

Put the #y#'s to one side, and the rest to the other.

Add #y# to both sides: #->2x=y+1# Now subtract #1# from both sides: #->2x-1=y->y=2x-1# In this the #2# that goes with the #x# is the slope, and #-1# is the #y#-intercept at #(0,-1)# graph{2x+1 [-14.24, 14.24, -7.11, 7.13]}
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Answer 2

To find the slope and y-intercept for the equation 2x - y = 1, you can rearrange the equation into slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.

First, solve the equation for y: 2x - y = 1 y = 2x - 1

Now, compare this equation to the slope-intercept form. The coefficient of x is the slope, and the constant term is the y-intercept.

So, the slope (m) is 2, and the y-intercept (b) is -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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