How do you find the slope and the y-intercept of the line #-4x+2y=-2#?

Answer 1

#"slope " =2," y-intercept " =-1#

The equation of a line in #color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))# where m represents the slope and b, the y-intercept.

The advantage to having the equation in this form is that m and b may be extracted 'easily'

Rearrange the given equation into this form.

add 4x to both sides.

#cancel(-4x)cancel(+4x)+2y=-2+4x#
#rArr2y=4x-2#

To obtain y as the subject, divide ALL terms on both sides by 2

#(cancel(2) y)/cancel(2)=4/2x-2/2#
#rArry=2x-1larr" in form y = mx + b"#

Extracting m and b gives.

#"slope " =m=2" and y-intercept " =b=-1#
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Answer 2

To find the slope and y-intercept of the line -4x + 2y = -2, rearrange the equation into slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept. -4x + 2y = -2 2y = 4x - 2 y = 2x - 1

Comparing with y = mx + b, the slope (m) is 2, and the y-intercept (b) is -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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