How do you find the slope and one point on the line that each point-slope equation represents for #y=3+2(x-1)#?

Answer 1
Gradient is #2# point is #(1,3)#
All you really got to do is to arrange that equation: #y = 3 + 2(x - 1)# in the form below
#y - y_0 = m(x - x_0)#
where #m# is the gradient and the point is #(x_0, y_0)#
#=> y - 3 = 2(x - 1)#
Hence, it's easy to see that #m = 2# and the point is #(1,3)#
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Answer 2

Point-slope equation:

#(y-y_1)=m(x-x_1)#
#y=3+2(x-1)#
#y-3=2(x-1)#
#y_1=3# and #x_1=1#
The point is (1,3) and the slope (#m#) is 2.
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Answer 3

The slope of the line represented by the point-slope equation y = 3 + 2(x - 1) is 2, and one point on the line is (1, 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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