How do you find the slope and intercept of #y + 4x = 8 #?

Answer 1

slope = -4, x-intercept = 2, y-intercept = 8

#y + 4x = 8# => write in slope-intercept form of: #y=mx+b# , where m = slope, b = the y-intercept: so in this case: #y = -4x + 8# => slope = -4 , the y-intercept = 8 to find the x-intercept set y to zero and solve for x: #0=-4x+8# #4x=8# #x=2# => the x-intercept

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Answer 2

Isaiah Anthony

To find the slope and y-intercept of the equation (y + 4x = 8), we need to rewrite it in the form (y = mx + b), where (m) is the slope and (b) is the y-intercept.

First, subtract (4x) from both sides to isolate (y):

[y = -4x + 8]

Comparing this with the standard form (y = mx + b), we see that the slope (m) is -4 and the y-intercept (b) is 8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.