How do you find the slope and intercept of #y= -2/5x + 20#?

Question

Abigail Allen · Accepted Answer

#"slope "=-2/5," y-intercept "=20#

#"the slope-intercept form of a line in "color(blue)" is"#.

# •color(white)(x)y=mx + b#

# "where m is the slope and b the y-intercept" #

This is how "#y=-2/5x+20" is written.

#"with y-intercept "=20#" and slope "=-2/5"

Kennedy Adams · Answer

Slope #= -2/5#

#y#-intercept #= 20# The provided equation is a straight line equation in the standard slope-intercept form. #y is equal to mx + c# where As a result, your equation's slope is #-2/5# and its #y#-intercept is #20#, matching the standard equation. plot{y = -2/5x + 20 [-40, 40, 80, -40]} If the slope is positive, the straight line only cuts the positive #y# axis, giving us the intercept; if the slope is negative, the tangent of the angle is greater than #180^@# and so, the straight line cuts the positive #x# axis. The #y#-intercept in this case is #20# because the straight line crosses the positive #y# axis at #(0,20)#.

Kennedy Adams · Answer

undefined To find the slope and intercept of the equation y = -2/5x + 20, you can identify the slope and intercept from the equation.

The slope of the equation is represented by the coefficient of x, which is -2/5.

The y-intercept is the value of y when x is equal to zero. In this equation, the y-intercept is 20.

So, the slope of the equation is -2/5 and the y-intercept is 20.