How do you find the slope and intercept of #y = 2/3 x#?

Question

Hazel Anglin · Accepted Answer

#m= 2/3 and c = 0#

In order to identify the slope and y-intercept from an equation of a straight line, it is easiest if it is the form #y =mx+c#

We have that form here: #y = 2/3x+0#

The slope is the numerical co-efficient of the x-term and the y-intercept is given by the constant term

#y = color(red)(m)x + color(blue)(c)#

#y = color(red)(2/3)x + color(blue)(0)#

Therefore the slope, #color(red)(m = 2/3)#

and the y-intercept is the point #color(blue)((0,0)#

Eva Abramson · Answer

#"slope "=2/3," y-intercept "=0# The equation of a line in #color(blue)"slope-intercept form"# is. #color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))# where m represents the slope and b, the y-intercept. #y=2/3x" is in this form as " y=2/3x+0# #rArr"slope "=m=2/3" and y-intercept "=b=0# graph{2/3x [-10, 10, -5, 5]}

Savannah Anderson · Answer

undefined To find the slope and intercept of the equation y = (2/3)x, we identify the slope as the coefficient of x, which is 2/3. The intercept occurs when x equals zero, so we plug in x = 0 into the equation to find the y-intercept. Therefore, the y-intercept is 0. Hence, the slope is 2/3, and the y-intercept is 0.