How do you find the slope and intercept of #x-y=10#?

Question

Julia Adams · Accepted Answer

Slope is #1#, #y#-intercept is #-10# and #x#-intercept is #10#.

The formula for a line's slope intercept is #y=mx+c#, where #m# is its slope and #c# is its intercept on #y#-axis So if you want to know slope of a line and its intercept n #x#-axis, just express #y# in terms of #x# and coefficient of #x# will be the slope and any constant term added to it will be its intercept on #y# axis. As we have #x-y=10#, this means #x-y+y=10+y# or #x=10+y# i.e. #10+y=x# and hence #10+y-10=x-10# or #y=x-10# i.e. the form which we desired Now as coefficient of #x# is #1#, slope of line #1# and as constant term is #-10#, #y#-intercept is #-10# In case you want #x# intercept, just put #y=0# in the equation #x-y=10# and we get #x-0=10# or #x=10# Hence #x#-intercept is #10# graph{x-10 [-19.67, -14.8, 5.2, -20.33]}

Eva Abramson · Answer

undefined To find the slope and intercept of the equation $ x - y = 10 $, first, rearrange it into slope-intercept form $ y = mx + b $. Then, identify the slope ($ m $) and the y-intercept ($ b $).

Rearranging the equation: 
$$ x - y = 10 $$
$$ y = x - 10 $$

So, the slope ($ m $) is $ 1 $ and the y-intercept ($ b $) is $ -10 $.