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How do you find the slope and intercept of #(x+1)/2 + (y+1)/2 = 1#?

Answer 1

Julia Adams

Slope: #(-1)#
y-intercept: #0#

Given #(x+1)/2+(y+1)/2=1#

We can multiply everything (on both sides) by #2# to get an equivalent equation: #color(white)("XXX")(x+1)+(y+1)=2#

Simplifying: #color(white)("XXX")x+y+2=2#

#color(white)("XXX")y=-x#

or, in slope intercept form: #color(white)("XXX")y=color(green)(""(-1))x+color(red)0# with slope #=color(green)(""(_1))# and y-intercept #color(red)0#

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Answer 2

Savannah Anderson

To find the slope and intercept of the equation (x+1)/2 + (y+1)/2 = 1, first rewrite the equation in slope-intercept form, which is y = mx + b. Then, identify the slope 'm' and the y-intercept 'b'. In this equation, isolate 'y' to solve for the slope-intercept form. The slope 'm' will be the coefficient of 'x', and the y-intercept 'b' will be the constant term. After rearranging the equation, the slope-intercept form becomes y = -x + 1. So, the slope 'm' is -1, and the y-intercept 'b' is 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.