How do you find the slope and intercept of #4x – 8y = 8#?

Question

Avery Alexander · Accepted Answer

Transforming the equation in #y=mx+q#.

When you have the equation in the format #y=mx+q# you call #m# the slope and #q# the intercept. So we need to transform the equation in that format. #4x-8y=8# first of all we put the terms with the #y# on the left and all the other terms on the right, remembering that when we make the "jump" of the #=# we have to change the sign. #-8y=-4x+8# Then we want to have only the #y# on the left, without the #-8#. To obtain it we divide left and right for #-8#. #\frac{-8y}{-8}=\frac{-4x}{-8}+\frac{8}{-8}# and doing the calculation, paying attention to do all the signs correctly, we obtain #y=1/2x-1#. We are now in the initial format where #m=1/2# and #q=-1#. So the slope is #1/2# and the intercept is #-1#.

Kennedy Adams · Answer

undefined To find the slope and intercept of the equation 4x - 8y = 8:

1. Solve the equation for y to put it in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
2. Subtract 4x from both sides: -8y = -4x + 8.
3. Divide both sides by -8 to isolate y: y = (1/2)x - 1.
4. Now, the equation is in the slope-intercept form, where the slope (m) is 1/2 and the y-intercept (b) is -1.

So, the slope is 1/2 and the y-intercept is -1.