How do you find the slope and intercept of #4x+2y-5=0#?

Answer 1

Rearrange the equation to get #m=-2, b=5/2#

A line's slope-intercept form is determined by

#y=mx+b#
where #m# is the slope and #b# is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:
#4x+2y-5=0#
First, we'll move the #4x# and the constant #-5# to the other side (by adding #-4x+5# to both sides):
#2y=-4x+5#
Now, we divide both sides of the equation by #2# to get #y# all by itself:
#y=-2 x+5/2#

We can observe that by contrasting this equation with the slope intercept form

#m=-2 , b=5/2#
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Answer 2

To find the slope and intercept of the equation 4x + 2y - 5 = 0:

Step 1: Rewrite the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. Step 2: Solve the equation for y: 2y = -4x + 5 Step 3: Divide both sides by 2 to isolate y: y = -2x + 5/2 Step 4: Compare the equation to y = mx + b, where m is the slope and b is the y-intercept. Step 5: The slope (m) is the coefficient of x, which is -2. Step 6: The y-intercept (b) is the constant term, which is 5/2. Step 7: Therefore, the slope is -2 and the y-intercept is 5/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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