How do you find the slope and intercept of #4x-2y=12#?

Question

Abigail Allen · Accepted Answer

#m=2#
#a=-6#
#b=3# Provided equation is #4x-2y=12#. The general slope equation is now #y-y_o=m(x-x_o)#, where #m# is the equation's slope. If we rewrite the given equation, we observe that it becomes #2y=4x-12#. Taking #y_o=0# into consideration, we take #4# common in the left-hand side and divide the entire equation by 2 to arrive at the desired result, which is #2y=4(x-3)# Divide by #2# and #y=2(x-3)#. When we compare the solution with the general equation, we observe that #m=2#. Once we rearrange the original equation, which was #4x-2y=12#, we get #x/3-y/6=1#. Since the #y# parameter has a negative value, #a=-6# and #b-3#. This is the general equation for the intercept form equation, which is #y/a=x/b=1#, where #a# is the y-intercept and #b# is the x-intercept.

Genesis Allen · Answer

undefined To find the slope and intercept of the equation 4x - 2y = 12:

1. First, solve the equation for y to put it in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
2. Subtract 4x from both sides: -2y = -4x + 12
3. Divide both sides by -2: y = 2x - 6
4. Now the equation is in slope-intercept form, where the slope (m) is 2, and the y-intercept (b) is -6.