How do you find the slope and intercept of #-2x - 3y = 1#?

Answer 1

We can convert to the slope intercept form, #y=mx +b# by isolating #y#, and then read the slope (#m#) and intercept (#b#) from the equation.

We can isolate #y# by first moving the #x# term, and then eliminating the coefficient of #y#
#-2x-3y=1#
We can move the x term by adding #2x# to both sides:
#cancel(2x)- cancel(2x)-3y=1+2x#
and clear the #y# coefficient by dividing both sides by #-3#
#(cancel(-3)y)/cancel(-3)=(1+2x)/-3#

and after that, we can rearrange and titrate to obtain our slope-intercept form:

#y=-2/3x-1/3#
So the slope and intercept are #-2/3# and #-1/3#, respectively.
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Answer 2

To find the slope and intercept of the equation -2x - 3y = 1, we need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

First, solve the equation for y: -2x - 3y = 1 -3y = 2x + 1 y = (-2/3)x - 1/3

Now, we can identify the slope and y-intercept: Slope (m) = -2/3 Y-intercept (b) = -1/3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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