How do you find the slope and intercept of #18x + 4y = 112#?

Answer 1

slope (m)=#-9/2#
intercept on x-axis=#56/9#
intercept on y-axis=#28#

The equation reads #18x+4y=112# #(18x)/112+(4y)/112=1# #(x/1)/(56/9)+y/28=1# intercept on the x-axis=#56/9# intercept on the y-axis=#28# slope (m)=#-9/2# as a result.

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Answer 2

Savannah Anderson

To find the slope and intercept of the equation (18x + 4y = 112):

Rewrite the equation in slope-intercept form, (y = mx + b), where (m) is the slope and (b) is the y-intercept.
Solve for (y).

Given equation: (18x + 4y = 112)

Subtract (18x) from both sides: (4y = -18x + 112)

Divide both sides by 4: (y = -\frac{18}{4}x + 28)

Thus, the slope ((m)) is (-\frac{18}{4}) and the y-intercept ((b)) is 28.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.