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How do you find the slope and intercept of #12x+4y-2=0#?

Answer 1

Hazel Anglin

Slope#=m=-3#

#y-#intercept#=b=1/2#

Solve the equation for #y:#

#12x+4y-2=0#

Add #2# to both sides:

#12x+4y=2#

Subtract #12x# from both sides:

#4y=2-12x#

Divide #4# from both sides:

#y=(2-12x)/4#

Simplify:

#y=1/2-3x#

#y=-3x+1/2#

This last equation is now in #y=mx+b# form where

#m# is the slope (the coefficient of the variable #x#)

#b# is the #y-#intercept or the constant

Based on the formula:

#y=-3x+1/2#

Slope#=m=-3#

#y-#intercept#=b=1/2#

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Answer 2

Ethan Adkins

To find the slope and intercept of the equation 12x + 4y - 2 = 0:

Rearrange the equation to the slope-intercept form, y = mx + b.
Solve for y to isolate it on one side of the equation.
Once in the slope-intercept form, the coefficient of x (12) represents the slope (m).
The constant term on the other side of the equation (-2) represents the y-intercept (b).

Therefore, the slope (m) is 12/4 = 3, and the y-intercept (b) is -2/4 = -1/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.