How do you find the slope and intercept of #-10x+4y=0#?

Question

Genesis Allen · Accepted Answer

#"slope "=5/2," intercept "=0# #"the equation of a line in "color(blue)"slope-intercept form"# is. #•color(white)(x)y=mx+b# #"where m represents the slope and b the y-intercept"# #"arrange "-10x+4y=0" into this form"# #"add 10x to both sides"# #cancel(-10x)cancel(+10x)+4y=0+10x# #rArr4y=10x+0# #"divide both sides by 4"# #(cancel(4) y)/cancel(4)=10/4x+0# #rArry=5/2x+0larrcolor(red)" in slope-intercept form"# #rArr"slope "=5/2," y-intercept "=0# graph{5/2x [-10, 10, -5, 5]}

Avery Alexander · Answer

Slope is #5/2# and y-intercept is #0#

# -10x +4y =0 or 4y =10x or y = 10/4x or y =5/2x #

The slope intercept form of a straight line is #y=mx+c # ,

where #m# is slope and #c# is y-intercept.

Comparing # y= 5/2x+0# with #y=mx+c # we get

Slope as #m=5/2# and y-intercept as # c=0#

graph{-10, 10, -5, 5]} [Ans] = -10x+4y

Nathan Axel · Answer

undefined To find the slope and intercept of the equation -10x + 4y = 0, you need to rearrange the equation into slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

1. Solve for y:
   -10x + 4y = 0
   4y = 10x
   y = (10/4)x
   y = (5/2)x

2. Compare the equation with y = mx + b:
   m (slope) = 5/2
   b (y-intercept) = 0

So, the slope is 5/2 and the y-intercept is 0.