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How do you find the slope and intercept of #1/3x+y=2#?

Answer 1

Nathan Axel

#"slope "=-1/3," y-intercept "=2#

#"the slope-intercept form of a line in "color(blue)" is"#.

# •color(white)(x)y=mx + b#

# "where m is the slope and b the y-intercept" #

"Rearrange 1/3x+y=2 into this form"

#"subtract "1/3x" from both sides"

Color(blue) #y=-1/3x+2larr"in slope-intercept form"#

#"with y-intercept "=2#" and slope "=-1/3"

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Answer 2

Abigail Allen

To find the slope and intercept of the equation 1/3x + y = 2, we first need to rearrange the equation into slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.

Starting with the given equation: 1/3x + y = 2 Subtract 1/3x from both sides to isolate y: y = -1/3x + 2

Now, comparing this equation with y = mx + b, we see that the slope (m) is -1/3 and the y-intercept (b) is 2. Therefore, the slope is -1/3 and the y-intercept is 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.