How do you find the restricted values of x or the rational expression #(x^3-2x^2-8x)/(x^2-4x)#?

Answer 1

#x!=0, 4#

Start by simplifying the equation:

#(x^3-2x^2-8x)/(x^2-4x)#
#=(x(x^2-2x-8))/(x(x-4))#
#=(x(x-4)(x+2))/(color(red)xcolor(blue)((x-4)))#
Recall that any fraction cannot have a denominator of #0#. To find the restrictions for #x#, set each polynomial or term in the denominator to cannot equal to #0#, and solve for #x#.

Finding the restrictions

#1. color(red)x!=0#
#2. color(blue)(x-4)!=0# #color(white)(ixxxx)x!=4#
#:.#, the restrictions are #x# are #x!=0# and #x!=4#.
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Answer 2

To find the restricted values of x for the rational expression (x^3-2x^2-8x)/(x^2-4x), we need to identify the values of x that would make the denominator equal to zero.

Setting the denominator, x^2-4x, equal to zero and factoring it, we get (x)(x-4) = 0.

This equation is satisfied when either x = 0 or x - 4 = 0.

Therefore, the restricted values of x for the given rational expression are x = 0 and x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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