How do you find the real solutions of the equation by graphing #6x^2=48x#?

Question

Avery Alexander · Accepted Answer

#x=0" and "x=8#

#color(blue)("Solving from the graph")#

Given:#" "6x^2=48x#

divide both sides by 6

#x^2=8x#

Subtract 8x from both sides

#x^2-8x=0#

Set as #y=x^2-8x# and plot the graph

Read of the values of #x# for which #y# is 0

Giving: #x=0" and "x=8#

Given that #x^2-8x=0#

#=>x^2=8x#

Divide both sides by #x#

#color(brown)(x=8 larr" First solution")#

Again consider # x^2=8x#

Known that 0 times any number gives 0

Let #x=0# giving

#x^2=8x" "->" "0xx0=8xx0" "->" "0=0 larr" True"#

#color(brown)("So "x=0 larr" Second solution")#

Nathan Axel · Answer

undefined To find the real solutions of the equation $6x^2 = 48x$ by graphing, first, rewrite it in the form $6x^2 - 48x = 0$. Then, graph the quadratic equation $y = 6x^2 - 48x$. The real solutions are the x-intercepts of the graph, where $y = 0$. Use the graph to identify these points, which represent the real solutions of the equation.