Home > Algebra > Function Notation

How do you find the range of each function given the domain: #h(n)=3n^2-2n+2; {-1,0,1}#?

Answer 1

Avery Alexander

Just evaluate each of the #x#-values within the function.

#h(-1) = 3(-1)^2 - 2(-1) + 2 = 3 + 2 + 2 = 7#

#h(0) = 3(0)^2 - 2(0) + 2 = 2#

#h(1) = 3(1)^2 - 2(1) + 2 = 3 - 2 + 2 = 3#

Hence, the range is #{2, 3, 7}#.

Hopefully this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Ethan Adkins

To find the range of the function h(n) = 3n^2 - 2n + 2 for the given domain {-1, 0, 1}, evaluate the function for each value in the domain and determine the range.

For n = -1: h(-1) = 3(-1)^2 - 2(-1) + 2 = 7 For n = 0: h(0) = 3(0)^2 - 2(0) + 2 = 2 For n = 1: h(1) = 3(1)^2 - 2(1) + 2 = 3

The range for the given domain is {2, 3, 7}.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.