# How do you find the range of each function given the domain: #h(n)=3n^2-2n+2; {-1,0,1}#?

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To find the range of the function h(n) = 3n^2 - 2n + 2 for the given domain {-1, 0, 1}, evaluate the function for each value in the domain and determine the range.

For n = -1: h(-1) = 3(-1)^2 - 2(-1) + 2 = 7 For n = 0: h(0) = 3(0)^2 - 2(0) + 2 = 2 For n = 1: h(1) = 3(1)^2 - 2(1) + 2 = 3

The range for the given domain is {2, 3, 7}.

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