How do you find the range given x=3-2t and y=2+3t for -2 ≤ t ≤ 3?

Answer 1
Given: #y=2+3t" [1]"# and #-2 <= t <= 3" [2]"#
Solve equation [1] for #t# in terms of #y#:
#y=2+3t" [1]"#
#3t = y-2#
#t = (y-2)/3" [1.1]"#

Substitute equation [1.1] into inequality [2]:

#-2 <= (y-2)/3 <= 3#

Multiply the inequality by 3:

#-6 <= y-2 <= 9#

Add 2 to the inequality:

#-4 <= y <= 11 larr# this is the range.
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Answer 2

#[-2,8]#

the range is the difference between the least point and highest point from the #x# axis
which are the #y# values
#y=2+3t#

Substiutute

#t=-2# #rarr" "##y=-2#
#t=3# #rarr" "##y=8#
so your range will be #[-2,8]#
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Answer 3

To find the range given x = 3 - 2t and y = 2 + 3t for -2 ≤ t ≤ 3, we first need to determine the range of values for x and y as t varies within the given interval.

For x = 3 - 2t, when t = -2, x = 3 - 2(-2) = 3 + 4 = 7 When t = 3, x = 3 - 2(3) = 3 - 6 = -3

So, the range of x values is from -3 to 7.

For y = 2 + 3t, when t = -2, y = 2 + 3(-2) = 2 - 6 = -4 When t = 3, y = 2 + 3(3) = 2 + 9 = 11

So, the range of y values is from -4 to 11.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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