# How do you find the quotient of #(x^3+27) / (x+3)#?

Long division of polynomials can be used. First, arrange the problem in long division format, with the numerator under the division sign and the denominator in front.

The quotient is since there is no remainder;

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To find the quotient of (x^3+27) / (x+3), we can use polynomial long division or synthetic division. Let's use polynomial long division:

Step 1: Divide x^3 by x, which gives us x^2. Step 2: Multiply x+3 by x^2, which gives us x^3+3x^2. Step 3: Subtract (x^3+3x^2) from (x^3+27), which gives us -3x^2+27. Step 4: Bring down the next term, which is 0. Step 5: Divide -3x^2 by x, which gives us -3x. Step 6: Multiply x+3 by -3x, which gives us -3x^2-9x. Step 7: Subtract (-3x^2-9x) from (-3x^2+27), which gives us 9x. Step 8: Bring down the next term, which is 0. Step 9: Divide 9x by x, which gives us 9. Step 10: Multiply x+3 by 9, which gives us 9x+27. Step 11: Subtract (9x+27) from (9x+0), which gives us -27.

Therefore, the quotient of (x^3+27) / (x+3) is x^2 - 3x + 9 with a remainder of -27.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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