How do you find the quotient of #(6b12)/(b+5)div(12b+18)#?
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To find the quotient of (6b12)/(b+5) divided by (12b+18), we can follow these steps:

Simplify the expression (6b12)/(b+5) by factoring out the greatest common factor, which is 6: (6b12)/(b+5) = 6(b2)/(b+5)

Simplify the expression (12b+18) by factoring out the greatest common factor, which is 6: (12b+18) = 6(2b+3)

Now, we can rewrite the division expression as a multiplication by taking the reciprocal of the divisor: 6(b2)/(b+5) ÷ 6(2b+3) = 6(b2)/(b+5) * 1/(6(2b+3))

Simplify the expression by canceling out common factors: 6(b2)/(b+5) * 1/(6(2b+3)) = (b2)/(b+5) * 1/(2b+3)
Therefore, the quotient of (6b12)/(b+5) divided by (12b+18) is (b2)/(b+5) * 1/(2b+3).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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