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How do you find the quotient of #(4x^2 – y^2) ÷ (2x – y)#?

Answer 1

Eva Adamson

#2x +y #

Take note of that

#(4x^2-y^2)/(2x-y)= ((cancel(2x-y))(2x+y))/(cancel(2x-y)) = 2x+y #

Since #a^2- b^2 = (a+b) (a-b)#

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Answer 2

Kennedy Adams

(2x +y)

( 4#x^2# - #y^2#) / #(2x -y) #

( 4#x^2# - #y^2#) can be written as #( 2x +y) (2x -y)#

#(2x +y ) ( 2x-y) // (2x-y) #

#2x +y#

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Answer 3

Savannah Anderson

To find the quotient of (4x^2 – y^2) ÷ (2x – y), you can use the method of long division or synthetic division. Would you like me to explain either of these methods in more detail?

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.